# solve for x |x+5| >= 3

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**Answer:**

Here's the answer

**Step-by-step explanation:**

x|x+5| = 3

x² + 5x =3

x²+5x-3 = 0

a=1, b=5, c= -3

By formula method,

b²-4ac = 5²-4 (1) (-3)

= 25 + 12

= 37

-b +- √b²-4ac

x=---------------------

2a

-5 +-√37

x= -------------

2×1

x= -5+√37 -5-√37

------------ or x = -----------

2 2

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