Question

solve for x, x+6 by 4 + x-3 = 5x-4 by 8​

Answer 1

Question :-

solve for x, x+6 by 4 + x-3 = 5x-4 by 8.

Solution :-

Given :

$\rm{ \frac{x + 6}{4 + x - 3} = \frac{5x - 4}{8} }$

Need to find :

• Value of x

Finding x

$\sf:\longmapsto{ \frac{x + 6}{4 + x - 3} = \frac{5x - 4}{8} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{ \frac{x + 6}{1 + x} = \frac{5x - 4}{8} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{8(x + 6) = (1 + x)(5x - 4)} \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{8x + 48 = 1(5x - 4) + x(5x - 4)} \: \\ \\ \sf:\longmapsto{8x + 48 = 5x - 4 + 5x {}^{2} - 4x} \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{8x + 48 + 4 = 5x {}^{2} + x} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{8x - x + 54 = 5x {}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{7x + 54 = 5x {}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf:\longmapsto{5x {}^{2} - 7x - 54 = 0 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

After solving we get a Quadratic equation.

But after seeing the equation we get the quadratic equation is not factorable.

Hence, the given expression will be incorrect.

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Solve for x:

X+6/4+x-3/5=5x-4/8

https://brainly.in/question/17748023