Question

solve for x
x-a/b+c + x-b/c+a + x-c/a+b=3

Answer 1

Answer:

If (x - a)/(b+c) + (x - b)/(c + a) + (x - c)/(a + b) = 3, then what is the value of x?

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Here's the fastest way I know how:

Subtract 3 from both sides but creatively:

x−ab+c−1+x−ba+c−1+x−ca+b−1=0

x−a−b−cb+c+x−a−b−ca+c+x−a−b−ca+b=0

Taking common:

(x−a−b−c)×k=0

Where k is some random expression in a,b, and c.

This implies,

x−a−b−c=0

x=a+b+c