Math, asked by seenasureshkmd, 4 months ago

Solve for x:{x cos(cot^(-1)x)+sin(cot^(-1)x)}^(2)=(51)/(50)

Answers

Answered by Anonymous
1

Step-by-step explanation:

After doing a

thorough research of the industry and marketing research, she launched an application-based

delivery app with the purpose of offering a complete solution to the urban foodies in terms of

food ordering and delivery from best restaurants located in the vicinity. After deliberations, she

decided to name it as QUICKY and hired a marketing manager to develop it further in terms of

utility that can be served through her offer. The marketing manager was further asked to define

other aspects of the element apart from what has been done.

I. Identify the element of marketing mix that is being discussed above.

II. Which aspect of the above identified element is taken by Tanya?

III. Describe the other aspects that are being expected by the marketing manager to define within

Answered by smrutitanayapradhan
1

Answer:

acosA + bsinB = c (1)

asinB - bcosA = k (2)

We need to find k

Lets square both the equations

(1)^{2}(1)

2

---->

(acosA + bsinB)^{2} = c^{2}(acosA+bsinB)

2

=c

2

a^{2} cos^{2}A+b^{2}sin^{2}B+2abcosAsinB = c^{2}a

2

cos

2

A+b

2

sin

2

B+2abcosAsinB=c

2

(3)

(2)^{2}(2)

2

---->

(asinB - bcosA)^{2} = k^{2}(asinB−bcosA)

2

=k

2

a^{2}sin^{2}B+b^{2}cos^{2}A-2absinBcosA = k^{2}a

2

sin

2

B+b

2

cos

2

A−2absinBcosA=k

2

(4)

Add (3) and (4)

a^{2} cos^{2}A+b^{2}sin^{2}B+2abcosAsinBa

2

cos

2

A+b

2

sin

2

B+2abcosAsinB +a^{2}sin^{2}A+b^{2}cos^{2}B-2absinBcosAa

2

sin

2

A+b

2

cos

2

B−2absinBcosA = c^{2}+k^{2}c

2

+k

2

a^{2}[cos^{2}A+sin^{2}A] +b^{2}[sin^{2}B+cos^{2}B]+2abcosAsinB-2absinBcosA = c^{2}+k^{2}a

2

[cos

2

A+sin

2

A]+b

2

[sin

2

B+cos

2

B]+2abcosAsinB−2absinBcosA=c

2

+k

2

a^{2}+b^{2}=c^{2}+k^{2}a

2

+b

2

=c

2

+k

2

k = \sqrt{a^{2}+b^{2}-c^{2}}k=

a

2

+b

2

−c

2

asinB-bcosA = \sqrt{a^{2}+b^{2}-c^{2}}asinB−bcosA=

a

2

+b

2

−c

2

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