Question

solve for x, x square - 3 x minus 9 equal to zero​

Answer 1

hope this helps youu!!!!!!!!!!!

Answer 2

Answer:

$3(\frac{ 1+\sqrt{5} }{2}), 3(\frac{1 -1\sqrt{5} }{2})$ is the required roots  of x for this given equation

Step-by-step explanation:

Explanation:

Given , x square - 3x minus 9 equal to zero

So, according to this statement we have ,

$x^{2} -3x -9 = 0$   ..........(i)

Step 1:

As we know ,

$D = \frac{-b +\sqrt{b^{2} -4ac} }{2a}$

So from the given equation we have

a = 1 , b = -3 and c = -9

Now ,  $D = \frac{+3+\sqrt{(-3)^{2} -4.1.-9} }{2.1}$

$D = \frac{+3 (+-)\sqrt{9 +36} }{2}$

⇒ $D = \frac{3 (+-)\sqrt{45} }{2}$

⇒$D = \frac{3 (+-)3\sqrt{5} }{2}$ ⇒ $D = \frac{3 +3\sqrt{5} }{2}, \frac{3 -3\sqrt{5} }{2}$

Therefore   x = $3(\frac{ 1+\sqrt{5} }{2}), 3(\frac{1 -1\sqrt{5} }{2})$.

Final answer :

Hence , $3(\frac{ 1+\sqrt{5} }{2}), 3(\frac{1 -1\sqrt{5} }{2})$ are the roots of x .

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