Question

Solve for x x square minus root 2 + 1 whole x + root 3 equal to zero

Answer 1

Find the value of x:

Step-by-step explanation:

$\ Given \ value:\\\\x^2-(\sqrt{2}+1)x+\sqrt{3}=0\\\\\ Find:\\\\x=?\\\\\ Solution:\\\ Formula:\\\\x= \frac{-b\pm \sqrt{b^2-4ac}}{2a} \\\\\ compare \ the \ value \ with \ ax^2+bx+c=0 \\\\a= 1\\b= -(\sqrt{2}+1)\\c= \sqrt{3} \\x= \frac{-b\pm \sqrt{b^2-4ac}}{2a} \\\\x= \frac {-(-(\sqrt{2}+1))\pm\sqrt{(-(\sqrt{2}+1))^2 - 4\times 1 \times \sqrt{3}}}{2\times 1}\\\\x= \frac {(\sqrt{2}+1)\pm\sqrt{(2+1+2\sqrt{2}) - 4\sqrt{3}}}{2} \\\\x= \frac {(\sqrt{2}+1)\pm\sqrt{3+2\sqrt{2} - 4\sqrt{3}}}{2}$

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