Solve for x;
x = [(tanA + cot A)^2] (sinA)^2 – (tan A)^2
Answers
Answered by
0
Answer:
mark brainlist please
Step-by-step explanation:
LHS=
(1+tan
2
A)
2
tanA
+
(1+cot
2
A)
2
cotA
(sec
2
A)
2
tanA
+
(cosec
2
A)
2
cotA
=
cos
4
A
1
cosA
sinA
+
sin
4
A
1
sinA
cosA
=sinAcos
3
A+cosAsin
3
A
=sinAcosA[sin
2
A+cos
2
A]
=sinAcosA=RHS
Hence proved.
Similar questions
Math,
16 hours ago
Math,
16 hours ago
Environmental Sciences,
16 hours ago
Chemistry,
1 day ago
Math,
8 months ago