Question

solve for x:
|x/x-1|+|x|=x^2/|x-1|

Answer 1

for x>1
$\frac{x}{x-1}+x= \frac{x^2}{x-1}$
$\frac{ x^{2}-x }{x-1}+x=0$
$\frac{x(x-1)}{x-1}+x=0$
$\frac{x^2-x+x^2-x}{y}= \frac{2x(x-1)}{x-1}=0$
 so for x>1 no solution
for x<1
there is only one solution x=0
so relation holds only for x=0

Answer 2

Answer:

|a|+|b|=|a+b|

ab>0

x^2/x-1>0

x=0    or   x>1

= x∈ {0} u[1,∞]

Step-by-step explanation: