Math, asked by apkinothing, 3 days ago

solve for x= x⅔ + x⅓ -2=0
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Answered by 11169
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Answer

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Answered by JashanR
174

Answer:

\huge{\mathcal{\color{red}{A}{\color{magenta}{N}{\color{olive}{S}{\color{black}{W}{\color{white}{E}{\color{blue}{R}}}}}}}}

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Given Equation:-

 \sf\large\star\: { \underline{ \color{skyblue} { :⟹ {x}^ { \frac{2}{3}  } +  {x}^{ \frac{1}{3} }   - 2 = 0}}}

 \sf{let \: {x}^{ \frac{1}{3} }   = y }

 \sf \bold \color{darkgreen}  {:⟹ {y}^{2}  + y - 2 = 0}

\sf {:⟹ {y}^{2}  + 2y - y - 2 = 0}

 \sf{:⟹y(y + 2) - 1( y + 2) = 0}

 \sf{:⟹(y + 2)(y - 1)}

 \sf \large \bold{ \fbox{ \color{orange}{:⟹y =  - 2,1  }}}

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 \sf{:⟹y =  - 2}

 \sf {:⟹{x}^{ \frac{1}{3}  }  =  - 2}

 \sf{:⟹{x = ( { - 2})^{3} }}

 \sf\large{ \fbox{ \color{lightgreen}{:⟹x =  - 8}}}

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 \sf{:⟹y = 1}

 \sf{ :⟹{x}^{ \frac{1}{3} } } = 1

 \sf{:⟹x =  ({1})^{3} }

 \sf\large{ \fbox{ \color{lightgreen}{:⟹x = 1}}}

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  \huge\sf{ \fbox{ \fbox{ \color{yellow}{:⟹∴x =  - 8,1}}}}

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