solve for x *x2+ 1 / x2 is equal to 17 /4
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Given;
- x² + 1/x² = 17/4
- x² + 1/x² ± 2(x)(1/x) = 17/4
- (x + 1/x)² - 2 = 17/4
- (x + 1/x)² = 17/4 + 2
- (x + 1/x)² = ( 17 + 8 )/4
- x + 1/x = √ ( 25/4 )
- x + 1/x = 5/2
- (x² + 1)/x = 5/2
- 2x² + 2 = 5x
- 2x² - 5x + 2 = 0
- 2x² - 4x - x + 2 = 0
- 2x(x-2) - 1(x-2) = 0
- (2x-1)(x-2) = 0
- at 2x - 1 = 0 => x = 1/2
- at x - 2 = 0 => x = 2
Thus x is either 1/2 or 2
#answerwithquality
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Value of x is either 2 or 1/2
Thanks!!!
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