Solve for x: x2-(√2+1)x+ 2 = 0
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Step-by-step explanation:
Given quadratic equation is x2-(√2 + 1)x+ √2 = 0
Put x = 1 in the above equation
LHS becomes, 1 - (√2 + 1) + √2 = 1 - √2 - 1+ √2 = 0
Hence '1' is the root of the given quadratic equation
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