Solve for x; x²-(√2+1)x+√2 = 0
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Answered by
4
Answer:
hey bro , well couldn't have started it off by saying , well this is in the nick of time..
x2-rootx-x+root=0(upon using distributive property )
rearrange it now , x2-x-root2x+root2-0
x(x-1)-root2(x-1)
therefore , (x-1)(x-root2)=0
x=root2
x=1
there you go buddy.
Step-by-step explanation:
Nahid1Siddique:
Thank you buddy..!
Answered by
8
By Sridharachariya formula, we get,

The square root of a negetive number does not exists in the set of Real Numbers.
So, x does not exist in real number. Therefore, this equation has no solutions.
The square root of a negetive number does not exists in the set of Real Numbers.
So, x does not exist in real number. Therefore, this equation has no solutions.
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