Question

Solve for x : x2
- 2ax + a2
- b
2
= 0.​

Answer 1

Answer:

SOLUTION :

Given :

x² - 2ax + (a² - b²) = 0

(x² - 2ax + a²) - (b²) = 0

(x)² - 2a×x + (a)² - b²

(x - a)² - (b)² = 0

[(a)² - 2ab + (b)² = (a - b)²]

(x - a - b) (x - a + b) = 0

[ a² - b² = (a - b)(a + b)]

x - a - b = 0 or x - a + b = 0

x = a + b or x = a - b

Hence, the value of x is (a +b) or (a-b).

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