Question

Solve for x : x² + (3 - 2a)x - 6a = 0
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Answer 1

Given : x² + (3 - 2a)x - 6a = 0

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➸ x² + (3 - 2a)x - 6a = 0

➸ x² + 3x - 2ax - 6a = 0

➸ x (x + 3) - 2a(x + 3) = 0

➸ (x + 3) (x - 2a) = 0 (Factorising left side)

➸ x + 3 = 0 or x - 2a = 0 (Zero - product rule)

➸ x = -3 or x = 2a

✯ Therefore,

• Hence, the roots of the given equation are -3, 2a.

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Answer 2

Given

x² + (3 - 2a)x - 6a = 0

=> x²+(3-2a)x-6a=0

=> x²+3x-2ax-6a=0

=> x(x+3)-2a(x+3)=0

=> (x+3)(x-2a) =0

=> x=-3 or x=2a

Therefore

• Roots of the given equation are -3,2a.