Question

solve for x. x2-3root5+10​

Answer 1

Step-by-step explanation:

Given quadratic equation:

x²-3√5x+10=0

Splitting the middle term,we

get

=>x²-2√5x-√5x+10=0

=>x²-2√5x-√5x+2×5=0

=>x²-2√5x+√5x+2×√5×√5=0

=>x(x-2√5)-√5(x-2√5)=0

=>(x-2√5)(x-√5)=0

=>x-2√5=0Orx-√5=0

=>x=2√5Orx=√5

Therefore,

RootsofgivenQuadratic equationare:

2√5Or√5

Answer 2

Answer:

$x {}^{2} - 3 \sqrt{5} + 10 \\ x {}^{2} - 2 \sqrt{5} x - \sqrt{5} x + 10 \\ x(x - 2 \sqrt{5} ) - \sqrt{5} (x - 2 \sqrt{5} ) \\ (x - 2 \sqrt{5} )(x - \sqrt{5} )$