Question

Solve for x :-

x² + ( 4 - 3y ) x - 12y = 0​

Answer 1

Question:

Solve for x:

x2 + (4 – 3y)x – 12y = 0

Solution:

Here, x2 + 4x – 3xy – 12y = 0

⟹ x(x + 4) - 3y(x + 4) = 0

or, (x + 4) (x – 3y) = 0

⟹ x + 4 = 0 or x – 3y = 0

⟹ x = -4 or x = 3y

Therefore, x = -4 or x = 3y

Answer 2

$\mathcal{\huge{\underline{\purple{Question:-}}}}$

Solve for x :-

x² + (4 - 3y)x - 12y = 0

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$\mathcal{\huge{\underline{\purple{Solution:-}}}}$

x² + (4 - 3y)x - 12y = 0

=> x² + 4x - 3xy - 12y = 0

=> x (x + 4) - 3y (x + 4) = 0

=> (x - 3y) (x + 4) = 0

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• x - 3y = 0

=> x = 3y

• x + 4 = 0

=> x = - 4

Hence, the value of x is 3y or - 4

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