★Solve for x= x²-4ax-b²+4a²=0 Do it If you can
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x2-4ax+4a2-b2=0
[x2-2*x*2a+(2a)^2]=b^2
(x-2a)^2=b^2
therefore
x-2a=+ or - b
x-2a=b or x-2a=-b
x=2a+b or x=2a-b
[x2-2*x*2a+(2a)^2]=b^2
(x-2a)^2=b^2
therefore
x-2a=+ or - b
x-2a=b or x-2a=-b
x=2a+b or x=2a-b
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