solve for x .x²-4ax-b²+4a²=0 pls help.dont answer if u don't know if the answer is wrong I will report,for genius answer I will mark u as brainliest.
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Answered by
3
Hey!!!
I'll solve this on paper for best understanding
Solved
=> x = 2a + b or
=> x = 2a - b
Refer to the attachment
Hope this helps
I'll solve this on paper for best understanding
Solved
=> x = 2a + b or
=> x = 2a - b
Refer to the attachment
Hope this helps
Attachments:
Answered by
3
x²-4ax+4a²-b² = 0
(x)²-2(x)(2a)+(2a)²-b² = 0
(a²-2ab+b² = (a-b)²)
(x-2a)² - b² = 0
[a²-b² = (a+b)(a-b)]
(x-2a+b)(x-2a-b) = 0
x = 2a-b. OR. x = 2a+b
(x)²-2(x)(2a)+(2a)²-b² = 0
(a²-2ab+b² = (a-b)²)
(x-2a)² - b² = 0
[a²-b² = (a+b)(a-b)]
(x-2a+b)(x-2a-b) = 0
x = 2a-b. OR. x = 2a+b
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