Question

Solve for x : x2-4ax-b2+4a2

Answer 1

X^2-4ax+4a^2-b^2=0

x^2-2*2a*x+(2a)^2-(b)^2=0

(x-2a)^2-(b)^2=0

(x-2a-b)(x-2a+b)=0

x-2a-b=0 x-2a+b=0

x=b+2a x=2a-b

HOPE IT HELPS YOU

PLZ MARK AS BRAINLIST☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️

Answer 2

$x^{2} - 4ax - b {?$