Question

solve for x:

x²-9/x+3=4/7..........fast​

Answer 1

$\sf{\displaystyle\dfrac{x^2-9}{x+3}=\dfrac{4}{7}}$

$\sf{\implies\displaystyle\dfrac{\left(x+3\right)\left(x-3\right)}{x+3}=\dfrac{4}{7}}$

$\sf{\implies\displaystyle x-3=\frac{4}{7}}$

$\sf{\implies\displaystyle x\cdot \:7-3\cdot \:7=\frac{4}{7}\cdot \:7}$

$\sf{\implies\displaystyle x\cdot \:7-21=4}$

$\sf{\implies\displaystyle x\cdot \:7-21+21=4+21}$

$\sf{\implies\displaystyle x\cdot \:7=25}$

$\sf{\implies x=\dfrac{25}{7}}$