Math, asked by deepdeol953, 8 months ago

Solve for x,y and z :x+y=4,y+z=1,z+x=1

Answers

Answered by silu12
3

ANSWER

(x,y,z) = (2,2,-1)

Solution:

x+y=4..............(1)

y+z=1.............(2)

z+x=1...............(3)

Adding eq(1),(2)&(3), we get

x+y+y+z+z+x= 4+1+1

=>x+y+z= 6/2=3

=>x+y+z= 3...........(4)

Now putting the value of eq(1) in eq(4)

we get,

4+z= 3

=>z= -1

Now putting the value of z in eq(2)

y+(-1)= 1

y= 2

Again put the value of y in eq(1)

x+2= 4

x= 4-2= 2

Similar questions