Solve for x,y and z :x+y=4,y+z=1,z+x=1
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(x,y,z) = (2,2,-1)
Solution:
x+y=4..............(1)
y+z=1.............(2)
z+x=1...............(3)
Adding eq(1),(2)&(3), we get
x+y+y+z+z+x= 4+1+1
=>x+y+z= 6/2=3
=>x+y+z= 3...........(4)
Now putting the value of eq(1) in eq(4)
we get,
4+z= 3
=>z= -1
Now putting the value of z in eq(2)
y+(-1)= 1
y= 2
Again put the value of y in eq(1)
x+2= 4
x= 4-2= 2
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