Question

Solve for x, y, z if
x2 + xy + xz = 6
y2 + yz + yx=30
z2 + zx + zy =18​

Answer 1

2x +xy+ xz=6

x(2+y+z) =6

x= 6/2+y+z

2y+yz+yx=30

y(2+z+x) =30

y = 30/2+z+x

2z+zx+zy=18

z(2+x+y) =18

z = 18/2+x+y