Math, asked by sreeramaps, 10 months ago

solve for xand y3x+y+1=0 and2x-3y+8=0​

Answers

Answered by Aloi99
4

Given:-

→3x+y+1=0๛(1)

→2x-3y+8=0๛(2)

\rule{200}{1}

To Find:-

The Value of x and y?

\rule{200}{1}

Answer:-

★Using Elimination Method★

•Multiply eq–(1)with 2 and Multiply eq–(2) with 3

→6x+2y+2=0

→6x+2y=-2๛(3)

→6x-9y+24=0

→6x-9y=-24๛(4)

♦Subtracting (3)&(4)♦

→6x+2y=-2

→6x-9y=-24

♠Signs Changed♠

→11y=22

→y= \frac{\cancel{22}}{\cancel{11}}

→y=2๛(5)

๛Using (5) in (1)๛

→3x+2+1=0

→3x+3=0

→3x=-3

→x= \frac{\cancel{-3}}{\cancel{3}}

→x=-1

\rule{200}{1}

★x=-1 and y=2★

\rule{200}{2}

Answered by Saby123
33

3x+y+1=0

2x-3y+8=0

•Multiply eq–(1)with 2 and Multiply eq–(2) with 3

6x+2y+2=0

6x+2y=-2

6x-9y+24=0

6x-9y=-24

Subtracting ...

6x+2y=-2

6x-9y=-24

11y=22

y=2

3x+2+1=0

3x+3=0

3x=-3

x=-1

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