Question

solve for y : 2y^2=3y

Answer 1

Answer:

$2 {y}^{2} = 3y \\ 2 {y}^{2} - 3y = 0 \\ 2 {y}^{2} - 2y - y = 0 \\ 2y(y - 1) - y = 0 \\ (2y - 1)( y - 1) = 0 \\ y = \frac{1}{2}, 1$