Math, asked by SmridhiBhadra, 1 year ago

solve for y :
2y² = 12 - 5y

Answers

Answered by Nishant5001
4
 {2y}^{2} + 5y - 12 = 0 \\ 2y {}^{2} + 8y - 3y - 12 = 0 \\ 2y(y + 4) - 3(y + 4) = 0 \\ (2y - 3)(y + 4) = 0 \\
y=3/2 or y= -4
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▶hope it help◀

Nishant5001: is it correct
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SmridhiBhadra: lemme check
Nishant5001: hmm why not
Nishant5001: ok bye
SmridhiBhadra: its correct thanks
Nishant5001: hmm my pl
Nishant5001: pleasure
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