Question

Solve for y (3y+1) ( 2y-1)=(6y+1)(y-3)

a)-⅕ b)-⅛ c)-1/7 d)1/7
دم -
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Answer 1

Answer:

Solve for y (3y+1) ( 2y-1)=(6y+1)(y-3)

b) -⅛

Answer 2

Answer:

(3y+1) (2y-1) = (6y+1) (y-3)

6y²- 3y+2y-1 = 6y²-18y+y-3

6y²-y-1 = 6y²-17y-3

6y²-6y²-y+17y-1+3=0

16y+2=0

y = -2/16

y= -1/8