Math, asked by itspopcorn, 9 months ago

Solve for y: (y + 1) / (2y+3) = 3 / 8



a)-1/2

b)1

c)-1

d)1/2

Solve for t : 2t -1 = -3 -t



a)2/3

b)-2/3

c)-2

d)-6

Answers

Answered by Anonymous
1

here is ur answer.....,...hope it hels

If it does plz mark brainliest

Attachments:
Answered by BrainlyRuby
1

\Large\underline\mathbb\blue{ANSWER}

1.  \tt{\frac{y + 1}{2y + 3}  =  \frac{3}{8} }

 \implies \tt{8(y + 1) = 3(2y + 3 )}

 \implies \tt{8y + 8 = 6y + 9}

 \implies \tt{8y - 6y = 9 - 8}

 \implies \tt{2y = 1}

 \implies \boxed{ \pink {\tt{y =  \frac{1}{2} } }}

2.  \tt{2t - 1 =  - 3 - t}

 \implies \tt{2t  + t =  -3 + 1}

 \implies \tt{3t =  - 2}

 \implies \boxed{ \pink{ \tt{t =  \frac{ - 2}{3} }}}

hope it's helpful ✅✅✅

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