Question

solve for y : (y/2)+1=(2y/5)-(3/2)​

Answer 1

★ Solution :-

In the question, we are given with an equation with a variable y. We were asked to find the value of that variable. The given equation is,

$\sf \leadsto \dfrac{y}{2} + 1 = \dfrac{2y}{5} - \dfrac{3}{2}$

We have two different methods to solve this equation. The first method is as follows,

$\sf \leadsto \dfrac{y}{2} + 1 = \dfrac{2y}{5} - \dfrac{3}{2}$

$\sf \leadsto \dfrac{y}{2} - \dfrac{2y}{5} = - \dfrac{3}{2} - 1$

$\sf \leadsto \dfrac{5y - 4y}{10} = \dfrac{ - 3 - 2}{2}$

$\sf \leadsto \dfrac{1y}{10} = \dfrac{ - 5}{2}$

$\sf \leadsto 2y = - 50$

$\sf \leadsto y = \dfrac{ - 50}{2}$

$\sf \leadsto y = - 25$

The second method is as follows,

$\sf \leadsto \dfrac{y}{2} + 1 = \dfrac{2y}{5} - \dfrac{3}{2}$

$\sf \leadsto \dfrac{y + 2}{2} = \dfrac{4y - 15}{10}$

$\sf \leadsto 10(y + 2) = 2(4y - 15)$

$\sf \leadsto 10y + 20 = 8y - 30$

$\sf \leadsto 10y - 8y = - 30 - 20$

$\sf \leadsto 2y = - 50$

$\sf \leadsto y = \dfrac{ - 50}{2}$

$\sf \leadsto y = - 25$

Therefore, the value of y is -25.

Answer 2

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