solve for y y^2+6y+27=0
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Answered by
3
Y^2 +9y - 3y + 27
Y(y+9) - 3(y-27)
(Y+9) (y - 3)
Y=-9 or y =3
I have answered in step-by-step so please mark me brainliest
Y(y+9) - 3(y-27)
(Y+9) (y - 3)
Y=-9 or y =3
I have answered in step-by-step so please mark me brainliest
vaishnavi8283:
solution is wrong
that was the other answer too
Answered by
1
HEY USER ____
HERE IS UR ANSWER _____
=> y ^2 + 6 y + 27 = 0
=> y ^2 + 9 y - 3 y + 27
=> y ( y + 9 ) - 3 ( y + 9 ) = 0
=> ( y - 3 ) ( y + 9 ) = 0
y = 3 , - 9 .
HERE IS UR ANSWER _____
=> y ^2 + 6 y + 27 = 0
=> y ^2 + 9 y - 3 y + 27
=> y ( y + 9 ) - 3 ( y + 9 ) = 0
=> ( y - 3 ) ( y + 9 ) = 0
y = 3 , - 9 .
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