Question

Solve for z. As soon as possible. Need it urgently

Answer 1

Answer:

Step-by-step explanation:

iz−1z−i=i(x+iy)−1x+iy−i=ix−(y+1)x+i(y−1)

=[ix−(y+1)][x−i(y−1)][x+i(y−1)][x−i(y−1)]

whose imaginary part is

=x2+y2−1x2+(y−1)2

which must be zero

⟹x2+y2=1

So, z must lie on the circle whose centre is (0,0) and radius =1