Math, asked by anupriya990, 11 months ago

solve.... friends....

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Answered by hemonshri73
1
cot^-1x+cot^-1y
cot^-1x=a. cot^-1y=b
x=cot a. y=cot b
cot(a-b)=(cot a cot b-1)÷cot b- tan a
cot(a-b)=xy+1/y-x
cot^-1x-cot^-1y=cot^-1 xy+1/y-x
Therefore,cot^-1x- cot^-1y=cot^-1xy+1/y-x
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