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let the marks be x and y
so x+y = 30.......equation one
now (x+2)×(y-3)......
now solve the equations simultaneously
xy-3x+2y-6....equation 2
therefore,
xy-3x+2y=6
3(x+y=30) = 3x+3y=90
=>. xy+5y=96
taking y common
x+5=96/y
therefore x=(96/y)-5
now by putting value of x in equation one 96/y-5+y=0
now solve it,
Pls mark as the brainliest answer
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