solve g(x)=x³+5x²-2x-10
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Solution:
g(x) = x^3 + 5x^2 - 2x - 10
Find the roots of the polynomial using factor theorem/remainder theorem
When we divide f(x) by the simple polynomial x - c we get:
f(x) = (x - c) * q(x) + r(x)
Or if we calculate f(c) and it is 0
... that means the remainder is 0, and
(x - c) must be a factor of the polynomial
If x = -5, then substitute to the given function.
x^3 + 5x^2 - 2x - 10
-5^3 + 5(-5)^2 - 2(-5) - 10
= -125 + 125 + 10 - 10 = 0
Therefore, x + 5 is the root of x^3 + 5x^2 - 2x - 10.
x^3 + 5x^2 - 2x - 10 = (x + 5) ( ?)
Using long division method.
(x^3 + 5x^2 - 2x - 10)/(x + 5) = (x^2 - 2)
x^3 + 5x^2 - 2x - 10 = (x + 5)(x^2 - 2)
(x + 5)(x^2 - 2) = 0
x + 5 = 0 or x^2 - 2 = 0
x = -5 or x = √2, -√2
x^2 - 2 = 0 The expression is not factorable with rational numbers.
Hope this will be helpful to you.
g(x) = x^3 + 5x^2 - 2x - 10
Find the roots of the polynomial using factor theorem/remainder theorem
When we divide f(x) by the simple polynomial x - c we get:
f(x) = (x - c) * q(x) + r(x)
Or if we calculate f(c) and it is 0
... that means the remainder is 0, and
(x - c) must be a factor of the polynomial
If x = -5, then substitute to the given function.
x^3 + 5x^2 - 2x - 10
-5^3 + 5(-5)^2 - 2(-5) - 10
= -125 + 125 + 10 - 10 = 0
Therefore, x + 5 is the root of x^3 + 5x^2 - 2x - 10.
x^3 + 5x^2 - 2x - 10 = (x + 5) ( ?)
Using long division method.
(x^3 + 5x^2 - 2x - 10)/(x + 5) = (x^2 - 2)
x^3 + 5x^2 - 2x - 10 = (x + 5)(x^2 - 2)
(x + 5)(x^2 - 2) = 0
x + 5 = 0 or x^2 - 2 = 0
x = -5 or x = √2, -√2
x^2 - 2 = 0 The expression is not factorable with rational numbers.
Hope this will be helpful to you.
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