Math, asked by aditimallesh12, 2 months ago

solve graphically 2x + Y =3 and X + 3 Y = -1



Can someone help pleaseeeee

Answers

Answered by amansharma264
6

EXPLANATION.

Graph of the equation.

⇒ 2x + y = 3. - - - - -(1).

⇒ x + 3y = -1. - - - - - (2).

As we know that,

From equation (1), we get.

⇒ 2x + y = 3. - - - - - (1).

Put the value of x = 0 in equation, we get.

⇒ 2(0) + y = 3.

⇒ y = 3.

Their Co-ordinates = (0,3).

Put the value of y = 0 in equation, we get.

⇒ 2x + (0) = 3.

⇒ 2x = 3.

⇒ x = 3/2.

⇒ x = 1.5.

Their Co-ordinates = (1.5,0).

From equation (2), we get.

⇒ x + 3y = -1. - - - - - (2).

Put the value of x = 0 in equation, we get.

⇒ (0) + 3y = -1.

⇒ 3y = -1.

⇒ y = -1/3.

⇒ y = -0.33.

Their Co-ordinates = (0,-0.33).

Put the value of y = 0 in equation, we get.

⇒ x + 3(0) = -1.

⇒ x = -1.

Their Co-ordinates = (-1,0).

Both curve intersect at a point = (2,-1).

Attachments:
Answered by Anonymous
7

{\large{\pmb{\sf{\underline{RequirEd \; Solution...}}}}}

Given that: We have to solve the following equation'(s) by graphical method. The equation is

{\small{\underline{\boxed{\sf{2x+y=3 \: and \: x+3y=-1}}}}}

Firstly let us assume,

{\sf{:\implies 2x+y=3 \dots Eq_{n} \: 1^{st}}}

{\sf{:\implies x+3y=-1 \dots Eq_{n} \: 2^{nd}}}

Now firstly in equation 1st let us put the term x as 0

{\sf{:\implies 2x+y=3}}

{\sf{:\implies 2(0)+y=3}}

{\sf{:\implies 0+y=3}}

{\sf{:\implies y=3}}

  • Henceforth, the coordinates be (0,3)

⋆ Now again in equation 1st let us put the term y as 0

{\sf{:\implies 2x+y=3}}

{\sf{:\implies 2x+0=3}}

{\sf{:\implies 2x=3}}

{\sf{:\implies x = 3/2}}

{\sf{:\implies x = 1.5}}

  • Henceforth, the coordinates be (1.5,0)

⋆ Now in equation 2nd let us put the term x as 0

{\sf{:\implies x+3y=-1}}

{\sf{:\implies 0+3y=-1}}

{\sf{:\implies 3y=-1}}

{\sf{:\implies y = -1/3}}

{\sf{:\implies y = -0.33}}

  • Henceforth, the coordinates be (0,-0.33)

Now again in equation 2nd let us put the term y as 0

{\sf{:\implies x+3y=-1}}

{\sf{:\implies x+3(0)=-1}}

{\sf{:\implies x+0=-1}}

{\sf{:\implies x=-1}}

  • Henceforth, the coordinates be (0,-1)

They intersect at (2,-1)

Graphs:

• The first graph is regards the whole solution that is 2x + y = 3 and x + 3y = -1

• The second attachment refer to x + 3y = -1

• The third attachment refer to 2x + y = 3

Attachments:
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