solve graphically 3x-5y+1=0,2x-y+3=0
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3x-5y+1=0 ---------(1)
2x-y+3=0 ----------(2)
multiplying eqn (2) by 5 we get
10x-5y+15=0 ---------(3)
subtracting eqn (3) from eqn (1) , we get
(3x-5y+1) - (10x-5y+15) =0-0
3x-5y+1-10x+5y-15=0
-7x-14=0
-7x=14
x = -2
putting the value of x = -2 in eqn (2) we get
2 (-2)-y+3=0
-4-y+3 =0
-y-1=0
-y=1
y = -1
x = -2 and y = -1
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