Question

solve graphically 3x+y=15 and 3x-4y=0​

Answer 1

Solution:

(graph is provided in the picture. refer to it)

two equations,

3x + y = 15 .....(i)

3x - 4y = 0 .....(ii)

(i)

3x = 15 - y (blue line)

or, x = 5 - y/3

creating points from this equation,

x | 4.67 | 4.3 | 4 |

----------------------------

y | 1 | 2 | 3 |

(ii)

3x - 4y = 0 (green line)

or, 3x = 4y

or, x = 4y/3

creating points from this equation,

x | 4 | 1.3 | 2.67 |

---------------------------

y | 3 | 1 | 2 |

plotting the points as different lines on the graph (picture).

As what to find is not provided in this question, I'm supposing that you need to find the Point of Intersection.

Answer : The point of intersection of two lines are (4, 3).

Tell me in the comments if the instructions are different.

Hope it helps.