Solve graphically 4x-3y=0 2x+3y-18=0, Also find the ratios of the triangles formed by these lines
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Step-by-step explanation:
4x−3y+4=0
⟹x=
4
−4+3y
Let, y=4, then x=
4
−4+3(4)
=2
Similarly, when y=0,x=−1
4x+3y−20=0
⟹x=
4
20−3y
Let, y=4, then x=
4
20−3(4)
=2
Similarly, when y=0,x=5
Plotting the above points on the graph, we get, the intersecting point i.e(2,4)
Area of the region bounded by these lines and x-axis =
2
1
×6units×4 units
=12 sq. units.
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