Math, asked by maihoonpriyansh, 3 months ago

Solve graphically 4x-3y=0 2x+3y-18=0, Also find the ratios of the triangles formed by these lines

Answers

Answered by Heroicheist
7

Step-by-step explanation:

4x−3y+4=0

⟹x=

4

−4+3y

Let, y=4, then x=

4

−4+3(4)

=2

Similarly, when y=0,x=−1

4x+3y−20=0

⟹x=

4

20−3y

Let, y=4, then x=

4

20−3(4)

=2

Similarly, when y=0,x=5

Plotting the above points on the graph, we get, the intersecting point i.e(2,4)

Area of the region bounded by these lines and x-axis =

2

1

×6units×4 units

=12 sq. units.

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