solve graphically: max z=4x1+4x2. subject to:x1+2x3<=10;6x1+6x2<=36;x1<6;x1,x2>=0
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Given : x1+2x2<=10;6x1+6x2<=36;x1<6;x1,x2>=0
To Find : max z=4x1+4x2.
Solution:
x₁ + 2x₂ ≤ 10
6x₁ + 6x₂ ≤ 36 => x₁ + x₂ ≤ 6
x₁ < 6
x₁ ≥ 0
x₂ ≥ 0
x₁ + 2x₂ ≤ 10
x₁ + x₂ ≤ 6
=> x₂ = 4 x₁ = 2
(x₁ , x₂) = ( 2 , 4) , ( 6 , 0) , ( 0 , 5)
Z = 4x₁ + 4x₂
(x₁ , x₂) = ( 2 , 4) => Z = 24
(x₁ , x₂) =, ( 6 , 0) => Z = 24
(x₁ , x₂) = ( 0 , 5) => Z = 20
(x₁ , x₂) = ( 2 , 4) => Z = 24 as x₁ < 6
Hence
(x₁ , x₂) = ( 2 , 4) => Z = 24
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