Question

Solve graphically the following LPP:

Max Z = 7x1 + 3x2

Subject to : x1 + 2x2 ≥ 3

x1 + x2 ≤ 4

0 ≤ x1 ≤ 2.5, 0 ≤ x2 ≤ 1.5

Answer 1

Answer:

To get C 5x1 + x2 = 10 … (1) x1 + x2 = 6 … (2) (1) – (2) ⇒ 4x1 = 4 ⇒ x1 = 1 x = 1 substitute in (2) ⇒ x1 + x2 = 6 ⇒ 1 + x2 = 6 ⇒ x2 = 5 ∴ C is (1, 5) To get B x1 + x2 = 6 x1 + 4x2 = 12 (1) – (2) ⇒ -3x2 = -6Read more on Sarthaks.com - https://www.sarthaks.com/987153/minimize-z-3x1-2x2-subject-to-the-constraints-5x1-x2-10-x1-x2-6-x1-4x2-12-and-x1-x2-0To get B x1 + x2 = 6 x1 + 4x2 = 12 (1) – (2) ⇒ -3x2 = -6 x2 = 2 x2 = 2 substitute in (1), x1 = 4 ∴ B is (4, 2)Read more on Sarthaks.com - https://www.sarthaks.com/987153/minimize-z-3x1-2x2-subject-to-the-constraints-5x1-x2-10-x1-x2-6-x1-4x2-12-and-x1-x2-0

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