Solve graphically the following pair of linear equations 3x+y=9;3x+4y=18 . Hence, find the vertices of the triangle formed by the above two lines and the x-axis.
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Answer:
x=2, y=3
Step-by-step explanation:
lets start with first equation
3x+y=9
y=9-3x
therefore ,
3x+4y=18
we got the value of y
3x+4(9-3x)=18
3x+36-12x=18
-9x+36=18
36-18=9x
18=9x
18/9=x. x=2
substituting the value of x in equation
3x+y=9. ,3(2)+y=9. 6+y=9
y=9-6
y=3
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