Math, asked by chauhan2977, 7 hours ago

Solve graphically the pair of equations 2x + 3y =11 and 2x - 4y = -24. Hence find the

value of m, given that the line represented by y = mx + 3 passes through the intersection of

the given pair​

Answers

Answered by amansharma264
35

EXPLANATION.

Solve graphically the pair of equations.

⇒ 2x + 3y = 11. - - - - - (1).

⇒ 2x - 4y = - 24. - - - - - (2).

As we know that,

From equation (1), we get.

⇒ 2x + 3y = 11. - - - - - (1).

Put the value of x = 0 in the equation, we get.

⇒ 2(0) + 3y = 11.

⇒ 3y = 11.

⇒ y = 11/3.

⇒ y = 3.66.

Their Co-ordinates = (0,3.66).

Put the value of y = 0 in the equation, we get.

⇒ 2x + 3(0) = 11.

⇒ 2x = 11.

⇒ x = 11/2.

⇒ x = 5.5.

Their Co-ordinates = (5.5,0).

From equation (2), we get.

⇒ 2x - 4y = - 24. - - - - - (2).

Put the value of x = 0 in the equation, we get.

⇒ 2(0) - 4y = - 24.

⇒ - 4y = - 24.

⇒ 4y = 24.

⇒ y = 6.

Their Co-ordinates = (0,6).

Put the value of y = 0 in the equation, we get.

⇒ 2x - 4(0) = - 24.

⇒ 2x = - 24.

⇒ x = - 12.

Their Co-ordinates = (-12,0).

Both curves intersects at a point = (-2,5).

To find value of m.

⇒ y = mx + 3.

Put the value of (x, y) = (-2, 5) in the equation, we get.

⇒ (5) = m(-2) + 3.

⇒ 5 = -2m + 3.

⇒ 5 - 3 = - 2m.

⇒ 2 = - 2m.

m = - 1.

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Answered by Itzheartcracer
19

Given :-

2x + 3y = 11

2x - 4y = -24

To Find :-

Value of m

Solution :-

From 1

2x + 3y = 11

Putting x as 0

2(0) + 3y = 11

3y = 11

y = 11/3

Co-ordinates = (0,11/3)

Putting y as 0

2y + 3(0) = 11

2y = 11

y = 11/2

Co-ordinates = (11/2,0)

From 2

Putting x as 0

2(0) - 4y = -24

0 - 4y = -24

-4y = -24

y = -24/-4

y = 24/4

y = 6

Co-ordinates = (0,6)

Putting y as 0

2x - 4(0) = -24

2x - 0 = -24

2x = -24

x = -24/2

x = -12

Co-ordinate = (-12,0)

Intersection point = (-2,5)

y = mx + 3

5 = m(-2) + 3

5 = -2m + 3

5 - 2 = -2m

2 = -2m

2/-2 = m

1/-1 = m

-1/1 = m

-1 = m

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