solve graphically the system of equations 4x-3y+4=0and 4x+3y-20=0.find the area bounded by these lines and x-axis
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the given set of linear equations are 4x-3y+4 =0 ......(1) and 4x+3y-20=0.......(2)
first we will plot these straight lines.
points (-1,0) and (0,3/4) satisfy the eq(1) plot the points and join them
points (5,0) and (5/4 ,5) satisfy eq(2) plot the points and join them.
now from the graph it is clear that the given lines intersect at point (2,4)
thus x =2 and y =4 is the solution of the given equation.
the shaded region is the required region.
area of the triangle ABC = 1/2 *base*height of the triangle ABC
= 1/2 *BC*4
=2BC
=2*6=12 sq units
hope this helps you.
cheers!!
first we will plot these straight lines.
points (-1,0) and (0,3/4) satisfy the eq(1) plot the points and join them
points (5,0) and (5/4 ,5) satisfy eq(2) plot the points and join them.
now from the graph it is clear that the given lines intersect at point (2,4)
thus x =2 and y =4 is the solution of the given equation.
the shaded region is the required region.
area of the triangle ABC = 1/2 *base*height of the triangle ABC
= 1/2 *BC*4
=2BC
=2*6=12 sq units
hope this helps you.
cheers!!
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