Question

solve graphically y=1/2x and 3x+ 4y-20=0​

Answer 1

Answer:

The given equations are

x-2y=0x−2y=0

3x+4y-20=03x+4y−20=0

Substitute x=0, in equation (1).

(0)-2y=0\Rightarrow y=0(0)−2y=0⇒y=0

Substitute x=2, in equation (1).

(2)-2y=0\Rightarrow y=1(2)−2y=0⇒y=1

It means line 1 passes through the point (0,0) and (2,1). Plot these two points on a coordinate plane and connect them by a straight line.

Substitute x=0, in equation (2).

3(0)+4y-20=0\Rightarrow y=53(0)+4y−20=0⇒y=5

Substitute x=4, in equation (2).

3(4)+4y-20=0\Rightarrow y=23(4)+4y−20=0⇒y=2

It means line 1 passes through the point (0,5) and (4,2). Plot these two points on a coordinate plane and connect them by a straight line.

From the below graph it is clear that the intersection point of both line is (4,2).

Therefore, the solution of the system of equations is (4,2).

Step-by-step explanation:

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