solve graphically Y=x^2-4x+5
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Step-by-step explanation:
This is a quadratic function of form
y
=
a
x
2
+
b
x
+
c
, with a=1, b=-4 and c=-5.
The graph will be a parabola.
Since a is positive, the arms go up.
To find the y-intercept, let x = 0 and find y = c = -5.
To find the x-intercepts, let y = 0 and use either factorizing or the quadratic formula to find the roots x = 5 or x = -1.
To find the turning point, set the derivative to zero.
∴
2
x
−
4
=
0
⇒
x
=
2
>
Then find y(2) = -9.
Then put all of this together to draw the graph as shown below :
graph{x^2-4x-5 [-22.49, 22.5, -11.24, 11.26]}
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