Question

SOLVE => x^2+x-182=0​

Answer 1

Answer:

${x}^{2} + x - 182 = 0 \\ = > {x}^{2} + 14x - 13x - 182 = 0 \\ = > x(x + 14) - 13(x + 14) = 0 \\ = > (x + 14)(x - 13) = 0 \\ = > (x + 14) = 0 \: \: or \: \: (x - 13) = 0 \\ = > x = ( - 14) \: \: or \: \: x = 13$

Step-by-step explanation:

Hence your answer is

${\boxed {x=(-14) \:or\:x=13}}$