solve how many three digit numbers are divisible by 5
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100,105,.....,995
d = 5
a1= 100
an = a+(n-1)d
995 = 100 +(n-1)5
995-100 = (n-1)5
895/5 = (n-1)
179+1=n
n = 180
so the 180 three digits numbers are divisible by 5
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