Question

Solve: (i) 13(x-4)-3(x-9)-5(x+4) =0

(ii) 16 =4 +3(t+2)​

Answer 1

Answer:

13

$13x - 56 - 3x + 27 - 5x - 20 = 0 \\ 13x - 3x - 5x - 56 +27 - 20 = 0 \\ 5x + 49 = 0 \\ 5x = 0 - 49 \\ 5x = 49 \\ x = 49 \div 5$

Answer 2

Answer:

i) The value of x is 9.

ii) The value of t is 2.

Step-by-step-explanation:

i)

The given equation is

13 ( x - 4 ) - 3 ( x - 9 ) - 5 ( x + 4 ) = 0.

We have to find the value of x.

Now,

13 ( x - 4 ) - 3 ( x - 9 ) - 5 ( x + 4 ) = 0

⇒ 13x - 52 - 3x + 27 - 5x - 20 = 0

⇒ 13x - 3x - 5x - 52 + 27 - 20 = 0

⇒ 10x - 5x - 52 + 7 = 0

⇒ 5x - 45 = 0

⇒ 5x = 45

⇒ x = 45 ÷ 5

⇒ x = 9

∴ The value of x is 9.

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ii)

The given equation is 16 = 4 + 3 ( t + 2 ).

We have to find the value of t.

Now,

16 = 4 + 3 ( t + 2 )

⇒ 3 ( t + 2 ) + 4 = 16

⇒ 3t + 6 = 16 - 4

⇒ 3t + 6 = 12

⇒ 3t = 12 - 6

⇒ 3t = 6

⇒ t = 6 ÷ 3

⇒ t = 2

∴ The value of t is 2.