Math, asked by Kavya0815, 4 months ago

solve:
i. (3÷2)^-2
ii. 5^-3
iii. (1÷6)-1

Answers

Answered by umeshnirmal04
3

Answer:

. 2 – 3/5

= ( 2 × 5 )/5 – 3/5

= 10/5 – 3/5

= ( 10 – 3 ) ÷ 5 = 7/5

ii. 4 + 7/8

= ( 4 × 8 )/8 + 7/8

= 32/ 8 + 7/8

= ( 32 + 7 )/8 = 39/8

iii. 3/5 + 2/7

= ( 3 × 7 ) ÷ ( 5 × 7 ) + ( 2 × 5 ) ÷ ( 7 × 5 )

= 21/35 + 10/35

= ( 21 + 10 ) ÷ 35 = 31/35

iv. 9/11 – 4/15

= ( 9 × 15 ) ÷ ( 11 × 15 ) – ( 4 × 11 ) ÷ ( 15 × 11 )

= 135/165 – 44/165

= ( 135 – 44 ) ÷ 165 = 91/ 165

v. 7/10 + 2/5 + 3/2

= 7/10 + ( 2 × 2 ) ÷ ( 5 × 2 ) + ( 3 × 5 ) ÷ (2 × 5 )

= 7/ 10 + 4/ 10 + 15/10

= ( 7 + 4 + 15 ) ÷10

= 26/ 10 = 13/5 = 2 3/5

vi. 2 2/3 + 3 1/2

= 8/3 + 7/2

= ( 8 × 2 ) ÷ ( 3 × 2 ) + ( 7 × 3 ) ÷ ( 2 × 3 )

= 16/6 + 21/ 6

= ( 16 + 21 ) ÷ 6 = 37/6 = 6 1/6

vii. 8 1/2 – 3 5/8

= 17/2 – 29/8

= ( 17 × 4 ) ÷ ( 2 × 4 ) – 29/ 8

= 68/8 – 29/8

= ( 68 – 29 ) ÷ 8 = 39/8 = 4 7/8

Answered by kshmashukla7a27
0

(i)2 – 3/5 = 2/1 – 3/5

                  = (2 * 5 – 3 * 1)/5                         [LCM (1, 5) = 5]

                  = (10 - 3)/5

                  = 7/5  

                  = 1              

(ii) 4 + 7/8 = 4/1 + 7/8          

                   = (4 * 8 + 7)/8                               [LCM (1, 8) = 8]

                   = (32 + 7)/8

                   = 39/8    

                   = 4        

   

(iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35                  [LCM (7, 5) = 35]

                        = (21 + 10)/35

                        = 31/35

Hope this was helpful

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