Math, asked by tungnathgupta19163, 18 days ago

Solve: (i), 4x - 2(3x - 5)+2/3(4x - 7).=0

Answers

Answered by naseemakhtar2326
1

Answer:

5x−(4x−7)(3x−5)=6−3(4x−9)(x−1)

5x−(12x

2

−20x−21x+35)=6−3(4x

2

−4x−9x+9)

5x−12x

2

+41x−35=6−12x

2

+39

46x−35=39x−21

7x=14

x=2

Answered by shreyanshsingh644
0

Answer:

12x-6(3x-5)+2(4x-7)= 0

12x-18x+30+8x-14 = 0

2x+16 = 0

2x = -16

x = -8

Step-by-step explanation:

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