Question

SOLVE (i) 8(p-3) = 64 (ii) -2(x+1)/6 = 0

Answer 1

Step-by-step explanation:

8 (p - 3) = 64

8p -24 = 64

8p = 64 + 24

8p = 88

p = 88/8

p = 11

-2(x + 1)/6 = 0

-2x - 2/6 = 0

-2x - 2 = 0 × 6

-2x -2 = 0

-2x = 0 + 2

-2x = 2

x = 2/-2

x = -2/2

x = -1

i hope it helps you

Answer 2

Answer:

$(i)8(p - 3) = 64 \\ = 8p - 24 = 64 \\ 8p = 64 + 24 \\ 8p = 88 \\ p = \frac{88}{8} \\ p = 11$

$(ii) \frac{ - 2(x + 1)}{6} = 0 \\ = \frac{ - 2x - 2}{6} = 0 \\ = - 2x - 2 = 0 \\ = - 2x = 2 \\ = x = \frac{2}{ - 2} \\ x = - 1$

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